If x = 3 + 8 , then x^2 + 1x^2 is equal to?

Answer: Option C

$$\begin{array}{rl}& \Rightarrow x=3+\sqrt{8}\\ & \Rightarrow x^2=9+8+2\times 3\sqrt{8}\\ & \Rightarrow x^2=17+6\sqrt{8}\\ & \Rightarrow \frac{1}{x^2}=17-6\sqrt{8}\\ & \therefore x^2+\frac{1}{x^2}\\ & =17+6\sqrt{8}+17-6\sqrt{8}\\ & =34\end{array}$$