If x + 1/x = 2, x ≠ 0, then the value of x^2 + 1x^3 is equal to?

Answer: Option B

$$\begin{array}{rl}& x+\frac{1}{x}=2\text{, }x\ne 0\\ & \text{Put }x=1\\ & 1+1=2\\ & \therefore x^2\text{ + }\frac{1}{x^2}\\ & =1+1\\ & =2\end{array}$$