If x + 1/x 0 and x^3 + 1x^3 = 0 , then the value ( x + 1/x )^4 is?

Answer: Option A

$$\begin{array}{rl}& x^3+\frac{1}{x^3}=0\\ & \text{It is possible only when}\\ & x+\frac{1}{x}=\sqrt{3}\\ & \text{So, }{\left(x+\frac{1}{x}\right)}^4={\left(\sqrt{3}\right)}^4\\ & \iff {\left(x+\frac{1}{x}\right)}^4=9\end{array}$$