If x2 - 3x - 1 = 0, then the value of (x2 + 8x - 1)(x3 + x-1)-1 is:

Answer: Option C

$$\begin{array}{rl}& x^2-3x-1=0\\ & x\left(x-3-\frac{1}{x}\right)=0\\ & x-\frac{1}{x}=3\\ & x^2+\frac{1}{x^2}=11\\ & \frac{\left(x^2+8x-1\right)}{x^3+\frac{1}{x}}\\ & =\frac{x\left(\frac{x-1}{x+8}\right)}{x\left(\frac{x^2+1}{x^2}\right)}\\ & =\frac{3+8}{11}\\ & =1\end{array}$$