In a circle with centre O, a diameter AB is produced to a point P lying outside the circle and PT is a tangent to the circle at the point C on it. If ∠BFT = 36°, then is the measure of ∠BCP?

Answer: Option D

∠BCP = ?
∠PCO = 90°   (PT is a Tangent)
In ΔPCO
∠COB = 180° - (36° + 90°) = 54°
Let ∠OCB = ∠OBC = θ   (∵ OC = OB)
In ΔOCB
2θ = 180°- 54°
θ = 63°
∠BCP = 90° - 63° = 27° Answer