In a game of 100 points, A can give B 20 points and C 28 points. Then, B can give C:

Answer: Option B

$$\begin{array}{rl}& A:B=100:80\\ & A:C=100:72\\ & \therefore \frac{B}{C}=\frac{B}{A}\times \frac{A}{C}=\frac{80}{100}\times \frac{100}{72}\\ & =\frac{10}{9}=\frac{100}{90}=100:90\\ & \therefore \text{B}\text{can}\text{give}\text{C}\text{10}\text{points}\end{array}$$