In a simultaneous throw of two dice, what is the probability of getting a doublet ?

Answer: Option A

In a simultaneous throw of dice, n (S) = (6 × 6) = 36
Let E = event of getting a doublet
= [(1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6)]
∴ P(E) = $$\frac{n(E)}{n(S)}$$ = $$\frac{6}{36}$$ = $$\frac{1}{6}$$