In a simultaneous throw of two dice, what is the probability of getting a total of 10 or 11?

Answer: Option D

In a simultaneous throw of two dice, we have n (S) = (6 × 6) = 36
Let E = event of getting a total of 10 or 11
= [(4, 6), (5, 5), (6, 4), (5, 6), (6, 5)]
$$\therefore P(E)=\frac{n(E)}{n(S)}=\frac{5}{36}$$