In a single throw of die, what is the probability of getting a number greater than 4 ?

Answer: Option B

When a die is thrown, we have S = {1, 2, 3, 4, 5, 6}
Let, E = event of getting a number greater than 4 = {5, 6}
$$\therefore P(E)=\frac{n(E)}{n(S)}=\frac{2}{6}=\frac{1}{3}$$