Q1273
In a totally irreversible isothermal expansion process for an ideal gas, ΔE = 0, ΔH = 0. Then ΔQ and ΔS will be
A.
ΔQ = 0, ΔS=0
B.
ΔQ = 0 , ΔS = +ve
AnswerC.
ΔQ = 0, ΔS = -ve
D.
ΔQ = +ve , ΔS= +ve
Answer: Option B
Solution
Answer: Option B
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