Q5
In a triangle ABC,∠ A = 90°, AL is drawn perpendicular to BC, Then ∠BAL is equal to:
In a triangle ABC,∠ A = 90°, AL is drawn perpendicular to BC, Then ∠BAL is equal to:
A.
∠ALC
B.
∠ACB
AnswerC.
∠BAC
D.
∠B - ∠BAL
Answer: Option B
Solution
Answer: Option B
Solution:
∠BAL + ∠B + 90° = 180°or, ∠BAL + ∠B = 90°
or, ∠BAL = 90° - ∠B - - - - - - - - (1)
Now, in ΔABC,
∠ACB + ∠B + ∠A = 180°
∠ACB = 90°
-∠B - - - - - (2)
From, (1) and (2),
∠BAL = ∠ACB