In a triangle ABC, incentre is O and ∠BOC = 110°, then the measure of ∠BAC is:

Answer: Option B

According to question,
Given : ∠BOC = 110°
∠BOC = 90° + $$\frac{1}{2}$$ ∠A

110° = 90° + $$\frac{\angle A}{2}$$
$$\frac{\angle A}{2}$$ = 20
∠A = 40°