Q13
In ΔABC, AD ⊥ BC, then
A.
AB2 - BD2 = AC2 - CD2
AnswerB.
AB2 + BD2 = AC2 - CD2
C.
AB2 - BD2 = AC2 + CD2
D.
AB2 - AC2 = BD2 + CD2
Answer: Option A
Solution
Answer: Option A
Solution:
In ΔADCAB2 = AD2 + BD2 - - - - - - - (1)
In Right angled Δ ACD,
AC2 = AD2 + BD2 - - - - - - - (2)
By (1) - (2)
AB2 - AC2 = BD2 - CD2
AB2 - BD2 = AC2 - CD2