In an equilateral ΔABC, the medians AD, BE and CF intersect to each other at point G. If the area of quadrilateral BDGF is 12√3 cm2, then the side of ΔABC is:

Answer: Option D

Solution

Answer: Option D

Solution:

$$\begin{array}{rl}& 2\text{ unit}\to 12\sqrt{3}\\ & 6\text{ unit}\to 12\sqrt{3}\times 3=36\sqrt{3}\\ & \text{Area}=\frac{\sqrt{3}}{4}{a}^2\\ & 36\sqrt{3}=\frac{\sqrt{3}}{4}{a}^2\\ & a=12\text{ cm}\end{array}$$