In an examination, B obtained 20%, more marks than those obtained by A, and A obtained 10% less marks than those obtained by C. D obtained 20% marks than those obtained by C. By what percentage are the marks obtained by D more than those obtained by A?

Answer: Option D

Solution

Answer: Option D

Solution:

Let C marks = 100

More = 120 - 90 = 30
More % $$=\frac{30}{90}\times 100=33\frac{1}{3}\%$$