In circular measure, the value of the angle 11° 15' is?

Answer: Option A

$$\begin{array}{rl}& \text{1}{\text{1}}^{\circ }\text{15’}=\text{1}\text{1}+\frac{\text{15}}{60}=11+\frac{1}{4}=\frac{{45}^{\circ }}{4}\\ & \text{We know }\pi \text{ radian}=180^{\circ }\\ & 1^{\circ }=\left(\frac{\pi }{{180}^{\circ }}\right)\text{radian,}\\ & \frac{{45}^{\circ }}{4}=\frac{\pi }{{180}^{\circ }}\times \frac{{45}^{\circ }}{4}\\ & =\frac{{\pi }^c}{16}\end{array}$$