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Mechanical Engineering · Q36

Heat And Mass Transfer

Engineering and GATE · Mechanical Engineering · question 36

Q36

In heat transfer, conductance equals conductivity (kcal/hr/sq.m/°C/cm) divided by

A.
Hr (time)
B.
Sq. m (area)
C.
°C (temperature)
D.
K.cal (heat)
Answer

Answer: Option D

Solution

Answer: Option D
Solution:
In heat transfer, conductance equals conductivity (kcal/hr/sq.m/°C/cm) divided by K.cal (heat)