In the given figure, ABCDEF is a regular hexagon whose side is 6 cm. APF, QAB, DCR and DES are equilateral triangles. What is the area (in cm2) of the shaded region?

Answer: Option C

Area of Hexagon $$=6\times \frac{\sqrt{3}}{4}{\left(6\right)}^2=54\sqrt{3}\text{ c}{\text{m}}^2$$
Area of one part of Hexagon $$=\frac{54}{6}\sqrt{3}=9\sqrt{3}$$
Required area $$=54\sqrt{3}+2\times 9\sqrt{3}=72\sqrt{3}\text{ c}{\text{m}}^2$$

Alternate Solution:
Counting the equilateral triangle figure = 8
Area of equilateral triangle is equal to $$=8\times \frac{\sqrt{3}}{4}\times 6\times 6=72\sqrt{3}\text{ c}{\text{m}}^2$$