In the given figure, AD is bisector of angle ∠CAB and BD is bisector of angle ∠CBF. If the angle at C is 34°, the angle ∠ADB is:

In the given figure, AD is bisector of angle ∠CAB and BD is bisector of angle ∠CBF. If the angle at C is 34°, the angle ∠ADB is:

Answer: Option C

Solution

Answer: Option C

Solution:

$$\begin{array}{rl}& \angle \text{D}=\frac{\angle \text{C}}{2}\left(\text{by angle bisector theorem}\right)\\ & \angle \text{D}=\frac{34}{2}\\ & \angle \text{D}=17^{\circ }\end{array}$$