In the given figure, radius of a circle is 14√2 cm. PQRS is a square. EFGH, ABCD, WXYZ and LMNO are four identical squares. What is the total area (in cm2) of all small squares?

Answer: Option B

Side of square PQRS
$$\begin{array}{rl}& =\frac{\text{Diameter of circle}}{\sqrt{2}}\\ & =\frac{14\sqrt{2}\times 2}{\sqrt{2}}\\ & =28\text{ cm}\end{array}$$

In ΔABO
AB = a
OB = 14√2
AO = 14 + 2a
OB² = AB² + OA²
(14√2)² = a² + (14 + 2a)²
196 × 2 = a² + 196 + 4a² + 56a
5a² + 56a - 196 = 0
5a² + 70a - 14a - 196 = 0
5a(a + 14) - 14(a + 14) = 0
(a + 14)(5a - 14) = 0
a = -14, a = $$\frac{14}{5}$$
Side of small square = 2a = $$\frac{28}{5}$$
Required Area $$=4\times {\left(\frac{28}{5}\right)}^2=125.44\text{ c}{\text{m}}^2$$