Q115
In ΔABC, AB = BC = K, AC = 2 k, then ΔABC is a :
In ΔABC, AB = BC = K, AC = k, then ΔABC is a :
A.
Right isosceles triangle
AnswerB.
Isosceles triangle
C.
Right-angled triangle
D.
Equilateral triangle
Answer: Option A
Solution
Answer: Option A
Solution:
∵ AB = BC = K
⇒ AC = K
⇒ (AC)2 = (AB)2 + (BC)2
⇒ ( K)2 = K2 + K2
⇒ 2K2 = 2K2
⇒ Therefore ΔABC will be a right isosceles triangle.