In ΔABC, the line parallel to BC intersect AB & AC at P & Q respectively. If AB : AP = 5 : 3, then AQ : QC is:

Answer: Option A

Solution

Answer: Option A

Solution:

$$\begin{array}{rl}& \frac{AP}{PB}=\frac{AQ}{QC}\\ & \frac{AQ}{QC}=\frac{3}{2}\\ & AQ:QC=3:2\end{array}$$