Q32
Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile: public class Test public static void main(String args[]) add(); add(1); add(1, 2); // insert code here
A.
void add(Integer... args){}
B.
static void add(int... args, int y){}
C.
static void add(int args...){}
D.
static void add(int[]... args){}
E.
static void add(int...args){}
AnswerAnswer: Option E
Solution
Answer: Option E
Solution:
var-args = variable number of arguments = 0 or manyvoid add(Integer... args){} is correct IF made "static" as it's called from a static context: main().
Var-args can be of both object(eg Integer) and primitive(eg int) types.
static void add(int... args, int y){} is correct IF its parameters' order is reversed.
If a method has both var-arg(0 or MAX 1) + non-var-args(0 or more) parameters then the var-arg parameter MUST come LAST!
static void add(int args...){} : "..." must come after the type of the var-arg parameter, not after its name
static void add(int[]... args){} : for this to be a correct declaration then add() should have been called something like this: "add(arr);" or "add(arr, arr);" where "arr" could be defined as "int[] arr = new int[5];"
static void add(int...args){} is a valid way to define var-args (there is no need to have any space between "..." and the type and name of the var-arg param)