( 3^25 + 3^26 + 3^27 + 3^28 ) is divisible by :

Answer: Option D

$$\begin{array}{rl}& \left(3^{25}+3^{26}+3^{27}+3^{28}\right)\\ & =3^{25}\left(3^0+3^1+3^2+3^3\right)\\ & =3^{25}\times 40\\ & =3^{24}\times 120\\ & \text{now check with option }\\ & \text{Only 30 can divide this}\text{.}\end{array}$$