Let 0 < x < 1, then the correct inequality is = ?

Answer: Option C

$$\begin{array}{rl}& 0<x<1,\\ & \text{Let }x=\frac{4}{10}\\ & \text{So},\sqrt{x}=\frac{2}{\sqrt{10}}\&\\ & x^2=\frac{16}{100}=0.16\\ & \text{Now},\\ & \because 0.16<\frac{4}{10}<\frac{2}{\sqrt{10}}\\ & \therefore x^2<x<\sqrt{x}\end{array}$$