Q112
Let N be the greatest number that will divide 1305, 4665 and 6905 leaving the same remainder in each case. Then sum of the digits in N is = ?
A.
4
AnswerB.
5
C.
6
D.
8
Answer: Option A
Solution
Answer: Option A
Solution:
N = HCF of (4665 - 1305) (6905 - 4665) and (6905 - 1305)= HCF of 3360, 2240 and 5600 = 1120
Sum of digits in N = (1 + 1 + 2 + 0) = 4