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Aptitude · Q621

Number System

Competitive Exams · Aptitude · question 621

Q621

Let x = 224 and y = 322. If the highest common factor of 23x and a × y is divisible by x and y, then what can be the possible value of a?

A.
4
B.
12
C.
8
D.
16
Answer

Answer: Option D

Solution

Answer: Option D
Solution:
x = 224, y = 322
⇒ 23x = 23 × 224 = 23 × 16 × 14
⇒ ay = 322a = a × 23 × 14
⇒ If HCF of 23x and ay is divisible by x and y then,
23 × 16 × 14 = a × 23 × 14
a = 16