Q632
Let x be the least number which when divided by 15,18, 20 and 27, the remainder in each case is 10 and x is a multiple of 31. What least number should be added to x to make it a perfect square?
A.
39
AnswerB.
37
C.
43
D.
36
Answer: Option A
Solution
Answer: Option A
Solution:
L.C.M. of 15,18, 20, 27 = 540x = 540K + 10

x = 540 × 4 + 10 = 2170
462 < 2170 > 472
472 = 2209
To make perfect square = 2209 - 2170 = 39