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Aptitude · Q632

Number System

Competitive Exams · Aptitude · question 632

Q632

Let x be the least number which when divided by 15,18, 20 and 27, the remainder in each case is 10 and x is a multiple of 31. What least number should be added to x to make it a perfect square?

A.
39
Answer
B.
37
C.
43
D.
36

Answer: Option A

Solution

Answer: Option A
Solution:
L.C.M. of 15,18, 20, 27 = 540
x = 540K + 10
Number System mcq question image
x = 540 × 4 + 10 = 2170
462 < 2170 > 472
472 = 2209
To make perfect square = 2209 - 2170 = 39