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Aptitude · Q135

Problems On H.C.F And L.C.M

Competitive Exams · Aptitude · question 135

Q135

Let x be the smallest number, which when added to 2000 make the resulting number divisible by 12, 16, 18 and 21. The sum of the digits of x is = ?

A.
6
B.
5
C.
7
Answer
D.
8

Answer: Option C

Solution

Answer: Option C
Solution:
LCM of 12, 16, 18, 21 = 1008
Next number = 1008 × 2 = 2016
Divisible by all
∴ 16 is added
Sum of digits = 1 + 6 = 7