ln ΔABC, ∠A = 66°. AB and AC are produced to points D and E, respectively. If the bisectors of ∠CBD and ∠BCE meet at the point O, then ∠BOC is equal to:

Answer: Option C

Solution

Answer: Option C

Solution:

$$\begin{array}{rl}& \angle A=66^{\circ }\\ & \angle BOC=?\\ & \angle BOC=90^{\circ }-\frac{\angle A}{2}\\ & =90^{\circ }-\frac{{66}^{\circ }}{2}\\ & =90^{\circ }-33^{\circ }\\ & =57^{\circ }\end{array}$$