Number 2, 4, 6, 8, 10.....196, 198, 200 are multiplied together. The number of zeros at the end of the product on the right will be equal to -

Answer: Option C

$$\begin{array}{rl}& \text{2, 4, 6, 8, 10}......\text{198, 200 }\\ & 2^{100}(1\times 2\times 3\times .....\times 99\times 100)\end{array}$$
$$\begin{array}{rl}& \underline{5|100}\\ & \underline{5|20}=24\text{ zero’s (20 + 4)}\\ & |4\end{array}$$
When we multiply the series of 1 × 2 × 3 ×..... × 100 then we find 24 zero at the end of the product