One black, one red and one green dice are thrown together, what is the probability of sum of three numbers is ≥ 17.

Answer: Option C

Total events = 6³ = 216
Sum greater than 17 = (6, 6, 6)
Sum equal to 17 = (6, 6, 5)(6, 5, 6)(5, 6, 6)
Probability = $$\frac{4}{216}$$ = $$\frac{1}{54}$$