Points A and B are 100 km apart on a highway. One car starts from A and another from B at the same time. If the cars travel in the same direction, they meet in 5 hours. If the cars travel towards each other, they meet in 1 hour. What is the speed of the faster car ?

Answer: Option B

According to the question,
Let the speed of the faster train = x km/hr
The speed of the slower train = y km/hr
$$\begin{array}{rl}& \text{Speed = }\frac{\text{Distance}}{\text{Time}}\\ & x+y=\frac{100}{1}\text{ km/hr and }\\ & x-y=\frac{100}{5}=20\text{ km/hr}\\ & x+y=\mathrm{100.....}(i)\\ & x-y=\mathrm{20.....}(ii)\end{array}$$
Solve equation (i) and (ii), we get
x = 60 km/hr
y = 40 km/hr
Speed of faster car = 60 km/hr