PQR is a triangle, whose area is 180 cm2. S is a point on side QR, such that PS is the angle bisector of ∠QPR. If PQ : PR = 2 : 3, then what is the area (in cm2) triangle PSR?

Answer: Option B

Solution

Answer: Option B

Solution:

$$\begin{array}{rl}& \frac{PQ}{PR}=\frac{2}{3}\\ & \therefore \frac{\text{ar }\Delta PSR}{\text{ar }\Delta PQR}=\frac{3}{2+3}=\frac{3}{5}\\ & 5\text{ units}=180\\ & 3\text{ units}=\frac{180}{5}\times 3=108\\ & \text{Area of }\Delta PSR=108\text{ c}{\text{m}}^2\end{array}$$