PQR is an isosceles triangle such that PQ = QR = 10 cm and ΔPQR = 90°. What is the length of the perpendicular drawn from Q on PR?

Answer: Option D

Solution

Answer: Option D

Solution:

$$\begin{array}{rl}& \frac{1}{2}\times 10\times 10=\frac{1}{2}\times 10\sqrt{2}\times \text{QS}\\ & \text{QS}=5\sqrt{2}\end{array}$$