Q51
Predict the output: public class Test public static void main(String args[]) try String arr[] = new String[10]; arr = null; arr[0] = "one"; System.out.print(arr[0]); catch(Exception ex) System.out.print("exception"); catch(NullPointerException nex) System.out.print("null pointer exception");
A.
"one" is printed.
B.
"exception" is printed.
C.
"null pointer exception" is printed.
D.
Compilation fails saying NullPointerException has already been caught.
AnswerE.
None of these
Answer: Option D
Solution
Answer: Option D
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