Ravi and Ajay start simultaneously from a place A towards B 60 km apart. Ravi's speed is 4km/h less than that of Ajay. Ajay, after reaching B, turns back and meets Ravi at a places 12 km away from B. Ravi's speed is:

Answer: Option C

Ajay → (x + 4) kmph.
A ________ 60 km _________ B
Ravi → x kmph.

Let the speed of Ravi be x kmph;
Hence, Ajay's speed = (x + 4) kmph;
Distance covered by Ajay = 60 + 12 = 72 km;
Distance covered by Ravi = 60 - 12 = 48 km.

According to question,
$$\begin{array}{rl}& \frac{72}{x+4}=\frac{48}{x}\\ & \text{or,}\frac{3}{x+4}=\frac{2}{x}\\ & \text{or,}3x=2x+8\\ & \text{or,}x=8\text{kmph}\end{array}$$