2^3.6 × 4^3.6 × 4^3.6 × (32)^2.3 = ( 32 )^?

Answer: Option A

$$\begin{array}{rl}& \text{Let }{2}^{3.6}\times 4^{3.6}\times 4^{3.6}\times (32{)}^{2.3}={\left(32\right)}^x\\ & \text{Then,}{2}^{3.6}\times {\left(2^2\right)}^{3.6}\times {\left(2^2\right)}^{3.6}\times (2^5{)}^{2.3}={\left(2^5\right)}^x\\ & \iff 2^{3.6}\times 2^{\left(2\times 3.6\right)}\times 2^{\left(2\times 3.6\right)}\times (2^5{)}^{2.3}={\left(2^5\right)}^x\\ & \iff 2^{\left(3.6+7.2+7.2\right)}\times (2^5{)}^{2.3}={\left(2^5\right)}^x\\ & \iff 2^{18}\times (2^5{)}^{2.3}={\left(2^5\right)}^x\\ & \iff {\left(2^5\right)}^{3.6}\times (2^5{)}^{2.3}={\left(2^5\right)}^x\\ & \iff {\left(2^5\right)}^{\left(3.6+2.3\right)}={\left(2^5\right)}^x\\ & \iff {\left(2^5\right)}^{5.9}={\left(2^5\right)}^x\\ & \iff x=5.9\end{array}$$