If 32x-y = 3x+y = 27 , the value of y is = ?

Answer: Option A

$$\begin{array}{rl}& {\text{3}}^{2x-y}\text{ = }{\text{3}}^{x+y}\text{ = }\sqrt{3^3}=3^{\frac{3}{2}}\\ & \iff 2x-y=\frac{3}{2}andx+y=\frac{3}{2}\\ & \iff 3x=\frac{3}{2}+\frac{3}{2}=3\\ & \iff x=1\\ & \therefore y=\left(\frac{3}{2}-1\right)=\frac{1}{2}\end{array}$$