1b:I[1254,["7330","static/chunks/d3ac728e-78c3d5d7a486ed3a.js","5159","static/chunks/5159-48592f0bf1a47f9d.js","8175","static/chunks/8175-f84d59b9bd013e10.js","8167","static/chunks/8167-b25693a0140130f2.js","664","static/chunks/664-bceb0f356f9312eb.js","3703","static/chunks/app/practice-question/%5Bslug%5D/page-d1408559b663b83f.js"],"PracticeQuestionCard"] 1c:T7b1,

Answer & Solution

Answer: Option B

Solution:

$$\eqalign{ & \sqrt {2\sqrt {2\sqrt {2\sqrt {2\sqrt 2 } } } } \cr & = \sqrt {2\sqrt {2\sqrt {2\sqrt {{{2.2}^{\frac{1}{2}}}} } } } \cr & = \sqrt {2\sqrt {2\sqrt {2\sqrt {{2^{\left( {1 + \frac{1}{2}} \right)}}} } } } \cr & = \sqrt {2\sqrt {2\sqrt {2\sqrt {{2^{\frac{3}{2}}}} } } } \cr & = \sqrt {2\sqrt {2\sqrt {2.{{\left( {{2^{\frac{3}{2}}}} \right)}^{\frac{1}{2}}}} } } \cr & = \sqrt {2\sqrt {2\sqrt {{{2.2}^{\left( {\frac{3}{2} \times \frac{1}{2}} \right)}}} } } \cr & = \sqrt {2\sqrt {2\sqrt {{{2.2}^{\frac{3}{4}}}} } } \cr & = \sqrt {2\sqrt {2\sqrt {{2^{\left( {1 + \frac{3}{4}} \right)}}} } } \cr & = \sqrt {2\sqrt {2\sqrt {{2^{\frac{7}{4}}}} } } \cr & = \sqrt {2\sqrt {2{{\left( {{2^{\frac{7}{4}}}} \right)}^{\frac{1}{2}}}} } \cr & = \sqrt {2\sqrt {{{2.2}^{\left( {\frac{7}{4} \times \frac{1}{2}} \right)}}} } \cr & = \sqrt {2\sqrt {{{2.2}^{\frac{7}{8}}}} } \cr & = \sqrt {2\sqrt {{2^{\left( {1 + \frac{7}{8}} \right)}}} } \cr & = \sqrt {2\sqrt {{2^{\frac{{15}}{8}}}} } \cr & = \sqrt {2{{\left( {{2^{\frac{{15}}{8}}}} \right)}^{\frac{1}{2}}}} \cr & = \sqrt {{{2.2}^{\frac{{15}}{{16}}}}} \cr & = \sqrt {{2^{\left( {1 + \frac{{15}}{{16}}} \right)}}} \cr &a

The value of 2 2 2 2 2 = ?

Solution