The value of 1 ( 216 )^ - 2/3 + 1 ( 256 )^ - 3/4 + 1 ( 32 )^ - 1/5 is = ?

Answer: Option A

$$\begin{array}{rl}& \frac{1}{{\left(216\right)}^{-\frac{2}{3}}}\text{ + }\frac{1}{{\left(256\right)}^{-\frac{3}{4}}}\text{ + }\frac{1}{{\left(32\right)}^{-\frac{1}{5}}}\\ & =\frac{1}{{\left(6^3\right)}^{-\frac{2}{3}}}\text{ + }\frac{1}{{\left(4^4\right)}^{-\frac{3}{4}}}\text{ + }\frac{1}{{\left(2^5\right)}^{-\frac{1}{5}}}\\ & =\frac{1}{6^{3\times \frac{\left(-2\right)}{3}}}\text{ + }\frac{1}{4^{4\times \frac{\left(-3\right)}{4}}}+\frac{1}{2^{5\times \frac{\left(-1\right)}{5}}}\\ & =\frac{1}{6^{-2}}\text{ + }\frac{1}{4^{-3}}\text{ + }\frac{1}{2^{-1}}\\ & =\left(6^2+4^3+2^1\right)\\ & =\left(36+64+2\right)\\ & =102\end{array}$$