( - 2 ^3 2 ^3 - )^2 + 1, θ ≠ 45° is equal to:

Answer: Option B

$$\begin{array}{rl}& {\left(\frac{\sin \theta -2{\sin }^3\theta }{2{\cos }^3-\cos \theta }\right)}^2+1\\ & =\frac{{\sin }^2\theta }{{\cos }^2\theta }{\left(\frac{{\cos }^2\theta }{{\cos }^2\theta }\right)}^2+1\\ & ={\tan }^2\theta +1\\ & ={\sec }^2\theta \end{array}$$