Solve 14 × 627 ÷ ( 1089 ) = (?)3 + 141

Answer: Option D

Let the missing number is a
Given,
$$\begin{array}{rl}& 14\times 627÷\sqrt{\left(1089\right)}={\left(a\right)}^3+141\\ & \frac{14\times 627}{\sqrt{1089}}={\left(a\right)}^3+141\\ & \frac{14\times 627}{33}=a^3+141\\ & 266=a^3+141\\ & a^3=125\\ & a=\text{root}3\text{of}125\\ & a=5\end{array}$$