Q208
tan(θ - 14π) is equal to:
A.
tanθ
AnswerB.
-cotθ
C.
cotθ
D.
-tanθ
Answer: Option A
Solution
Answer: Option A
Solution:
tan(θ - 14π)= -tan(14π - θ)
= -(-tanθ)
= tanθ
Aptitude · Q208
Trigonometry
Competitive Exams · Aptitude · question 208
= -tan(14π - θ)
= -(-tanθ)
= tanθ