The 3rd and 6th term of an arithmetic progression are 13 and -5 respectively. What is the 11th term?

Answer: Option D

T₃ = a + 2d = 13 ...... (1)
T₆ = a + 5d = -5 ...... (2)
on solving (1) and (2) d = -6 & a = 25
T₁₁ = a + 10d
      = 25 + 10(-6)
      = -35