Q30
The 7th and 12th term of an arithmetic progression are -15 and 5 respectively. What is the 16th term?
A.
25
B.
29
C.
21
AnswerD.
33
Answer: Option C
Solution
Answer: Option C
Solution:
T7 = a + 6d = -15 ....... (1)T12 = a + 11d = 5 ...... (2)
on solving (1) and (2)
d = 4 & a = -39
T16 = a + 15d
= -39 + 15(4)
= -39 + 60
= 21