The angle of depression of a car, standing on the ground, from the top of a 75 m tower, is 30°. The distance of the car from the base of the tower (in metres) is

Answer: Option C

AB is a tower and AB = 75 m
From A, the angle of depression of a car C
on the ground is 30°

$$\begin{array}{rl}& \text{Let distance }BC=x\\ & \text{Now in right }\Delta ACB,\\ & \tan \theta =\frac{AB}{BC}\\ & \Rightarrow \tan 30^{\circ }=\frac{75}{x}\\ & \Rightarrow \frac{1}{\sqrt{3}}=\frac{75}{x}\\ & \Rightarrow x=75\sqrt{3}m\\ & \therefore BC=75\sqrt{3}m\end{array}$$