The average of the first 100 positive integers is -

Answer: Option C

According to the question,
As we know that average of 'n' positive integer is
= $$\frac{n(n+1)}{2\times n}$$
= $$\frac{(n+1)}{2}$$
Here n = 100
∴ $$\frac{100+1}{2}$$
= $$\frac{101}{2}$$
= 50.5