The average price of 10 books is Rs. 12 while the average price of 8 of these books is Rs. 11.75. Of the remaining two books, if the price of one book is 60% more than the price of the other, what is the price of each of these two books?

Answer: Option C

Total price of the two books
= Rs. [(12 × 10) - (11.75 × 8)]
= Rs. (120 - 94)
= Rs. 26
Let the price of one book be Rs. x
Then, the price of other book
= Rs. (x + 60 % of x)
= Rs. $$\left(x+\frac{3}{5}x\right)$$
= Rs. $$\left(\frac{8x}{5}\right)$$
So, $$x+\frac{8x}{5}$$   = 26
⇒ 13x = 130
⇒ x = 10