The diameter of a 120 cm long roller is 84 cm. It takes 500 complete revolutions of the roller to level a ground. The cost of levelling the ground at Rs. 1.50 sq. m. is:

Answer: Option D

According to the question,
Diameter = 84 cm
Radius = 42 cm = 0.42 m
Height = 120 cm = 1.2 m
CSA of cylinder = 2πrh
$$=2\times \frac{22}{7}\times 0.42\times 1.2$$
Total area covered to planed in 500 rounds
$$\begin{array}{rl}& =2\times \frac{22}{7}\times 0.42\times 1.2\times 500\\ & \text{Total cost}=\left(2\times \frac{22}{7}\times 0.42\times 1.2\times 500\right)\times 1.50\\ & =\text{Rs}\text{. }2376\end{array}$$